使用锚标记登录后如何显示用户名

debugcn 发表于 Dev

拉帕阿修罗

我想通过使用锚标记显示当前用户名，但它不显示用户名。我已经在代码的最顶部包含了数据库连接和sesstion_start。我尝试了其他方法，但似乎没有用。我无法使代码正确运行。我希望有一个人可以帮助我。谢谢

   <li>
            <a href="<?php
                   if(isset($_SESSION['FirstName'])){
                       echo 'Welcome'.', '.$_SESSION['FirstName']." ".$_SESSION['LastName'];
                                }
                        ?>"></a>
                        <ul>
                            <li style="padding-left: 6px; padding-bottom: 10px;"><a href="#">History</a></li>
                            <li style="padding-left: 1px; padding-bottom: 10px;"><a href="#">Teachers</a></li>
                            <li style="padding-left: 10px; padding-bottom: 10px;"><a href="#">About</a></li>
                            <li style="padding-left: 6px; padding-bottom: 10px;"><a href="logout.php?logout-submit=logout" name="logout"> Logout </a></li>
                        </ul>
                    </li>

登录代码：

<?php
    include "includes/config.php";
    
  session_start();
if(isset($_POST['loginbutton'])){

$username = mysqli_real_escape_string($con,$_POST['user']);
$password = mysqli_real_escape_string($con,$_POST['password']);





    $sql_query = "SELECT * FROM tbl_useraccounts WHERE employee_id = '$username'";
    $result = mysqli_query($con,$sql_query);



 $row=mysqli_fetch_array($result);

            $passwordhashed = password_verify($password, $row['password']);
    if($passwordhashed){
            $_SESSION['username'] = $row['employee_id'];
            $_SESSION['usertype'] = $row['usertype'];
            if($_SESSION['usertype'] == 'Admin'){
             echo "<script>alert('Successfully logged in!');</script>";
             header('location: HomeForAdmin.php');
             die();
            }
            if($_SESSION['usertype'] == 'SuperAdmin'){
                echo "<script>alert('Successfully logged in!');</script>";
                header('location: HomeForSuperAdmin.php');
                die();
            }
            else{
                echo "<script>alert('Incorrect username and password!');document.location='login2.php'</script>";
            }
    }
    
    else{
        echo "<script>alert('Incorrect credentials!');document.location='login2.php'</script>";
    }

            $_SESSION['username'] = $row['employee_id'];
            $_SESSION['password'] = $row['password'];
            $_SESSION['usertype'] = $row['usertype'];
            $_SESSION['first_name'] = $row['FirstName'];
            $_SESSION['last_name'] = $row['LastName'];
            



}



?>`

穆法兹米

您尝试正确。而不是在里面写东西href=""。在锚标记内写下。

例如：

<a>Users Name</a>

码

<a href=""><?php
  if(isset($_SESSION['first_name'])){
    echo 'Welcome'.', '.$_SESSION['first_name']." ".$_SESSION['last_name'];
  }
?></a>

登录页面中的问题

在您的主页中，您正在检查从未设置的“名字”会话。

isset($_SESSION['FirstName'])

您正在尝试打印该会话值。

echo 'Welcome'.', '.$_SESSION['FirstName']." ".$_SESSION['LastName'];

在登录页面中，您可以使用该键设置会话的名字first_name和姓氏和last_name。

而不是使用与FirstName和相同的键来访问会话，该键LastName不存在。

尝试使用此代码登录页面。

<?php
    include "includes/config.php";
    
    session_start();
    if(isset($_POST['loginbutton']))
    {
        $username = mysqli_real_escape_string($con,$_POST['user']);
        $password = mysqli_real_escape_string($con,$_POST['password']);

        $sql_query = "SELECT * FROM tbl_useraccounts WHERE employee_id = '$username'";
        $result = mysqli_query($con,$sql_query);

        $row=mysqli_fetch_array($result);

        $passwordhashed = password_verify($password, $row['password']);
        if($passwordhashed)
        {
            $_SESSION['username'] = $row['employee_id'];
            $_SESSION['usertype'] = $row['usertype'];
            $_SESSION['password'] = $row['password'];
            $_SESSION['usertype'] = $row['usertype'];
            $_SESSION['first_name'] = $row['FirstName'];
            $_SESSION['last_name'] = $row['LastName'];
            if($_SESSION['usertype'] == 'Admin'){
             echo "<script>alert('Successfully logged in!');</script>";
             header('location: HomeForAdmin.php');
             die();
            }
            if($_SESSION['usertype'] == 'SuperAdmin'){
                echo "<script>alert('Successfully logged in!');</script>";
                header('location: HomeForSuperAdmin.php');
                die();
            }
            else{
                echo "<script>alert('Incorrect username and password!');document.location='login2.php'</script>";
            }
        }
        else{
            echo "<script>alert('Incorrect credentials!');document.location='login2.php'</script>";
        }
    }
?>

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。