如何根据用户输入重置代码？

debugcn 发表于 Dev

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我想根据用户输入重置代码，如果是，则重置代码，如果不停止则重置代码。我知道这是一个非常糟糕的代码，很抱歉我还在学习:)

import random

tool = input("Choose your weapon (R)ock (P)aper (S)cissors ")

computer = random.choice(["Rock", "Paper", "Scissors"])

if tool == "R" and computer == "Paper":
    print("You lost aganist ",computer,"!")

elif tool == "R" and computer == "Scissors":
    print("You won aganist! ",computer,"!")

elif tool == "R" and computer == "Rock":
    print("That's a tie!")

elif tool == "P" and computer == "Rock":
    print("You won aganist ",computer,"!")

elif tool == "P" and computer == "Scissors":
    print("You lost aganist ",computer,"!")

elif tool == "P" and computer == "Paper":
    print("That's a tie!")

elif tool == "S" and computer == "Rock":
    print("You lost aganist ",computer,"!")

elif tool == "S" and computer == "Paper":
    print("You won aganist ",computer,"!")

elif tool == "S" and computer == "Scissors":
    print("That's a tie!")

Maritn Ge

将其放在while循环中，并要求重复此操作，如果他拒绝，则将bool设置为no。顺便说一句，这忽略了错误的输入，您应该检查他的输入是否合法，就像我在这里所做的那样

import random

playing = True

while playing:

    tool = input("Choose your weapon (R)ock (P)aper (S)cissors ")

    computer = random.choice(["Rock", "Paper", "Scissors"])

    if tool == "R" and computer == "Paper":
        print("You lost aganist ",computer,"!")

    #...

    elif tool == "S" and computer == "Scissors":
        print("That's a tie!")

    else:
        print("Wrong input! Sorry!")

    play_again = input("Do you want to play again? y/n")
    
    if (play_again == "n"):
        playing = False