删除以元音js开头的对象键

debugcn 发表于 Dev

约翰·皇冠

我需要删除所有键，这些键从对象的元音开始，但是我不知道该怎么做。到目前为止，这就是我所拥有的。在此示例中，仅应保留“ chip”键，而所有其他键均应删除。你们能帮我吗？

'use strict'

function removeVowelKeys(object) {
  for (let key in object) {
    if (key[0] === 'a' || key[0] === 'A' || key[0] === 'u' || key[0] === 'U' ||
    key[0] === 'i' || key[0] === 'I' || key[0] === 'o' || key[0] === 'O' ||
    key[0] === 'e' || key[0] === 'E' || key[0] === 'y' || key[0] === 'Y' ) {
      delete object.key
  }
}
}


console.log(removeVowelKeys({
  alarm: 'This is SPARTA!!!',
  chip: 100,
  isValid: false,
  Advice: 'Learn it hard',
  onClick: 'make it great again',
}));

威尔·詹金斯

您需要从函数中返回对象，但也不应在对其进行循环时从对象中删除键。

这样的事情会做到这一点：

const removeVowelKeys = (obj) =>
  Object.fromEntries(
    Object.entries(obj).filter(
      ([k]) => !["a", "e", "i", "o", "u"].includes(k.toLowerCase()[0])
     )
  );

console.log(removeVowelKeys({
  alarm: 'This is SPARTA!!!',
  chip: 100,
  isValid: false,
  Advice: 'Learn it hard',
  onClick: 'make it great again',
}));

我还修复了您的原始方法，以便在遍历对象之前复制该对象，并使用[square bracket]表示法正确使用您的键：

function removeVowelKeys(obj) {
  for (let key in { ...obj }) {
    if (
      key[0] === "a" ||
      key[0] === "A" ||
      key[0] === "u" ||
      key[0] === "U" ||
      key[0] === "i" ||
      key[0] === "I" ||
      key[0] === "o" ||
      key[0] === "O" ||
      key[0] === "e" ||
      key[0] === "E" ||
      key[0] === "y" ||
      key[0] === "Y"
    ) {
      delete obj[key];
    }
  }
  return obj;
}

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