从子shell退出整个bash脚本

我对bash脚本有点陌生，我有一个C ++程序通过一些命名管道与该bash脚本来回通信。我使用了inotifywait来监视文件夹中的新文件，并在添加新文件（以.job结尾）时通过管道将其发送到。

我正在用C ++程序将结果送回管道，如果结果是“退出”，则我希望bash脚本退出执行。

我试图通过出口1完成此操作，如下所示，但是这似乎并没有退出整个脚本。相反，在运行该出口之后，当我将另一个文件放入监视文件夹时，脚本结束。

我阅读了一些有关subshel​​l的信息，想知道这是否与它们有关，以及有关如何退出整个脚本的任何建议。

DROP_FOLDER="$1"
DATA_FOLDER="$2"
OUTPUT_FOLDER="$3"
PATH_TO_EXECS="./tmp/"
PATH_TO_COMPLETED="../completed/"

# create pipes
read_pipe=/tmp/c_to_bash
write_pipe=/tmp/bash_to_c

if [[ ! -p $read_pipe ]]; then
    mkfifo $read_pipe
fi

if [[ ! -p $write_pipe ]]; then
    mkfifo $write_pipe
fi

# start c++ program 
./tmp/v2 $DATA_FOLDER $OUTPUT_FOLDER $PATH_TO_EXECS "${write_pipe}" "${read_pipe}" &


# watch drop folder
inotifywait -m $DROP_FOLDER -e create -e moved_to |
    while read path action file; do
        # ends in .tga
        if [[ "$file" =~ .*tga$ ]]; then 

            # move to image dir
            mv "${DROP_FOLDER}${file}" "${DATA_FOLDER}${file}" 
        fi
        
        # ends in .job
        if [[ "$file" =~ .*job$ ]]; then
            # pipe to dispatcher 
            echo "${DROP_FOLDER}${file}" > $write_pipe

            # wait for result from pipe
            if read line <$read_pipe; then
                echo $line
                # check for quit result
                if [[ "$line" == 'quit' ]]; then
                    # move job file to completed
                    mv "${DROP_FOLDER}${file}" "${PATH_TO_COMPLETED}${file}"
                    # exit
                    exit 1
                fi

                # check for continue result
                if [[ "$line" == 'continue' ]]; then
                    # move job file to completed
                    mv "${DROP_FOLDER}${file}" "${PATH_TO_COMPLETED}${file}"
                fi
            fi
        fi
    done