假设我有两个这样的清单，
Ii = [[7,1],[7,5],[7,8],[5,8],[2,8],[3,5]]
ci = [11,5,3,5,5,4]
现在，我要列出另一个mxn清单（I），如下所示：
I =
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[11, 0, 0, 0, 5, 0, 0, 3, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 4, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
我尝试了这段代码，
m,n = 8,10
I = [[0 for j in range(n)] for i in range(m)]
for i, j in Ii:
I[m - i][j - 1] = 1
有一个输出看起来像这样，
I =
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[1, 0, 0, 0, 1, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 1, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
现在我有1个想要ci值的地方。但是我想将ci的值放在1的位置。需要有关如何执行此操作的帮助吗？
m = 8
n = 10
Ii = [[7,1],[7,5],[7,8],[5,8],[2,8],[3,5]]
ci = [11,5,3,5,5,4]
I = [[0 for j in range(n)] for i in range(m)]
for z, *j, in enumerate(Ii):
for i, k in j:
I[m-i][k-1] = ci[z]
for i in I:
print(i)
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[11, 0, 0, 0, 5, 0, 0, 3, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 4, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
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