在OperationQueue中打印1到10不打印整数

debugcn 发表于 Dev

哈宁亚

我正在研究Combine Scheduler，我从Raywenderlich的书中获得了示例代码

let queue = OperationQueue()

let subscription = (1...10).publisher
  .receive(on: queue)
  .sink { value in
    print("Received \(value) on thread \(Thread.current.number)")
  }

这本书解释了OperationQueue使用所有可用线程，因此打印顺序和线程可能是随机的。我理解这部分，但是当我在操场上运行此代码时，我只看到10个数字中的5个。

Received 1 on thread 7
Received 2 on thread 6
Received 3 on thread 5
Received 7 on thread 9
Received 6 on thread 4

为什么该代码不能显示全部10个数字？

查尔斯·玛丽亚

您需要导入PlaygroundSupport并PlaygroundPage.current.needsIndefiniteExecution = true在文件顶部设置。

如果您使用另一个接收器方法，也将获得一个完成处理程序块的接收器方法，则在该完成处理程序中，您应调用 PlaygroundPage.current.finishExecution()

编辑：调用PlaygroundPage.current.finishExecution()队列上的障碍块，否则在您的打印语句全部执行之前被调用。

这是我的测试代码：

PlaygroundPage.current.needsIndefiniteExecution = true

let queue = OperationQueue()

let subscription = (1...10).publisher
    .receive(on: queue)
    .sink(receiveCompletion: { _ in
        queue.addBarrierBlock {
            print("Finished")
            PlaygroundPage.current.finishExecution()
        }
    }, receiveValue: { value in
        print("Received \(value) on thread \(Thread.current)")
    })

并输出：

Received 1 on thread <NSThread: 0x7fd86f204080>{number = 2, name = (null)}
Received 2 on thread <NSThread: 0x7fd86f404340>{number = 3, name = (null)}
Received 3 on thread <NSThread: 0x7fd86f404430>{number = 4, name = (null)}
Received 7 on thread <NSThread: 0x7fd86f405240>{number = 5, name = (null)}
Received 6 on thread <NSThread: 0x7fd86f205c50>{number = 6, name = (null)}
Received 10 on thread <NSThread: 0x7fd86ce487f0>{number = 7, name = (null)}
Received 5 on thread <NSThread: 0x7fd86cf048a0>{number = 10, name = (null)}
Received 9 on thread <NSThread: 0x7fd86ce49b20>{number = 11, name = (null)}
Received 4 on thread <NSThread: 0x7fd86cf2a4c0>{number = 12, name = (null)}
Received 8 on thread <NSThread: 0x7fd86ce4ad60>{number = 13, name = (null)}
Finished

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