//Input:
s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
//Expected output: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"
我的代码当前正在输出什么：
(CORWILL ALFRED) (CORWILL FRED) (CORWILL RAPHAEL) (CORWILL WILFRED) (TORNBULL BARNEY) (TORNBULL BETTY) (TORNBULL BJON)
我尝试了多种方法，例如在重新分配s（字符串）时更改开头的字符替换方式，这样一来我就不会删除逗号，然后不得不替换它们...但是当我这样做了，我的正则表达式不再起作用了，我不确定为什么会这样。因此，我试图找到另一个正则表达式来使用，以便能够解决该问题，但这同样很痛苦，所以我决定坚持以这种方式解决：尝试找到在第一个之间找到逗号的方法，和括号中的姓氏。
完整的问题和代码：
/*Could you make a program that
• makes this string uppercase
• gives it sorted in alphabetical order by last name.
When the last names are the same, sort them by first name. Last name and first name of a guest come in the result between parentheses separated by a comma.
*/
function meeting(s) {
s = s.replace(/:/g, ", ").toUpperCase();
//order alphabetically based on Last, then first name
const semicolon = ';'
let testArr = s.split(semicolon)
testArr.sort(function compare(a, b) {
var splitA = a.split(",");
var splitB = b.split(",");
var firstA = splitA[0]
var firstB = splitB[0]
var lastA = splitA[splitA.length - 1];
var lastB = splitB[splitB.length - 1];
if (lastA < lastB) return -1;
if (lastA > lastB) return 1;
if (firstA < firstB) return -1; //sort first names alphabetically
if (firstA > firstB) return 1;
return 0; //if they are equal
})
//print last names before first names with regex
let newArr = [];
for (let i = 0; i < testArr.length; i++) {
let variable = (testArr[i].replace(/([\w ]+), ([\w ]+)/g, "$2 $1"))
let comma = ","
newArr.push(`(${variable})`)
}
let finalStr;
finalStr = newArr.toString().replace(/[ ,.]/g, " ").toUpperCase();
// finalStr = finalStr.replace(/" "/g, ", ")
return finalStr
}
s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
console.log(meeting(s))
// expected result: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"
任何帮助将不胜感激，我花了大约5个小时解决这个问题。我使用的正则表达式是将姓氏的位置更改为名字的位置（Fred Corwill）->（Corwill Fred）。如果除了我正在使用的正则表达式之外，还有其他我可以给你建议的正则表达式，也许我也可以通过这种方式解决该问题，到目前为止，我尝试过的所有其他方法都没有在这里使用。
这看起来比需要的复杂得多。用;s分割后，将每个单独的元素以相反的顺序映射到其单词，然后加入：
const s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
const output = s
.toUpperCase()
.split(';')
.sort((a, b) => {
const [aFirst, aLast] = a.split(':');
const [bFirst, bLast] = b.split(':');
return aLast.localeCompare(bLast) || aFirst.localeCompare(bFirst);
})
.map((name) => {
const [first, last] = name.split(':');
return `(${last}, ${first})`;
})
.join('');
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