我有这段代码可以迭代Lua表“ childrenTable”以检索其值,但是我希望它们按“ symbolicname” 列然后按“ name”列排序
local JSON = require 'dkjson'
local childrenTable = {}
childrenTable[1] = {symbolicname = "02 CONNECTOR", path = "system/core/b connector", name = "b connector"}
childrenTable[2] = {symbolicname = "02 CONNECTOR", path = "system/core/a connector", name = "a connector"}
childrenTable[3] = {symbolicname = "01 CORE", path = "/system/core/b", name = "b"}
childrenTable[4] = {symbolicname = "01 CORE", path = "/system/core/a", name = "a"}
for index,value in ipairs(childrenTable) do print(JSON.encode(value)) end
现在返回此结果:
{"name":"b connector","symbolicname":"02
CONNECTOR","path":"system/core/b connector"}
{"name":"a connector","symbolicname":"02
CONNECTOR","path":"system/core/a connector"}
{"name":"b","symbolicname":"01 CORE","path":"/system/core/b"}
{"name":"a","symbolicname":"01 CORE","path":"/system/core/a"}
但我希望它按顺序返回列表:
{"name":"a","symbolicname":"01 CORE","path":"/system/core/a"}
{"name":"b","symbolicname":"01 CORE","path":"/system/core/b"}
{"name":"a connector","symbolicname":"02
CONNECTOR","path":"system/core/a connector"}
{"name":"b connector","symbolicname":"02
CONNECTOR","path":"system/core/b connector"}
提前致谢,
罗杰
使用table.sort
函数,它将遍历表并在当前索引的左侧和右侧向您传递一个项目。(table.sort
基于quicksort算法)
这将为您工作:
local childrenTable = {}
childrenTable[1] = {symbolicname = "02 CONNECTOR", path = "system/core/b connector", name = "b connector"}
childrenTable[2] = {symbolicname = "02 CONNECTOR", path = "system/core/a connector", name = "a connector"}
childrenTable[3] = {symbolicname = "01 CORE", path = "/system/core/b", name = "b"}
childrenTable[4] = {symbolicname = "01 CORE", path = "/system/core/a", name = "a"}
table.sort(childrenTable, function(a, b)
if a.symbolicname < b.symbolicname then
return true
else
if a.name < b.name then
return true
else return false end
end
return false
end)
for k,v in pairs(childrenTable) do print(k, v.name, v.symbolicname) end
另外,对于大量数据,请考虑使用数据框。
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我来说两句