我有一个包含健身房的物件，上面有可用的设备：
const gyms = [
{
"name": "gym1",
"equipmentAvailable": ["nothing"]
},
{
"name": "gym2",
"equipmentAvailable": ["jump rope","stationary bike","barbell"]
},
{
"name": "gym3",
"equipmentAvailable": ["kettlebell","dumbbell"]
},
{
"name": "gym4",
"equipmentAvailable": ["barbell","kettlebell","jump rope"]
}
]
我还列出了下一次锻炼所需的设备清单（然后将其转换为Set）：
const availableNeeded = ["barbell","jump rope"]
const equipmentSet = new Set(availableNeeded);
目前，我正在使用.find（）拉出第一个符合我的设备需求的健身房：
const filteredWorkouts = gyms.find(workout => (
workout.equipmentAvailable.some(equipment => equipmentSet.has(equipment))
))
console.log(filteredWorkouts)
自然，这总是返回Gym2，因为它是第一个与所需设备匹配的健身房。但是，有时我想将其切换并转到Gym4，因为它也具有所需的设备，但是find（）无法提供。
我将如何随机分配Gym输出，以便可以输出Gym2或Gym4？
使用.filter而不是.find获取可能匹配的数组，然后从数组中获取随机元素：
const gyms = [
{
"name": "gym1",
"equipmentAvailable": ["nothing"]
},
{
"name": "gym2",
"equipmentAvailable": ["jump rope","stationary bike","barbell"]
},
{
"name": "gym3",
"equipmentAvailable": ["kettlebell","dumbbell"]
},
{
"name": "gym4",
"equipmentAvailable": ["barbell","kettlebell","jump rope"]
}
];
const availableNeeded = ["barbell","jump rope"];
const filteredWorkouts = gyms.filter(gym => (
availableNeeded.every(equip => gym.equipmentAvailable.includes(equip))
));
const result = filteredWorkouts[Math.floor(Math.random() * filteredWorkouts.length)];
console.log(result);本文收集自互联网，转载请注明来源。
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