我的数据为：
(ID001,List((BookType,[text]),(author,xyz abc),(time,01/12/2019[22:00] CST/PM))),(ID002,List((BookType,[text]),(author,klj fgh),(time,19/02/2019[12:00] CST/AM)))
我需要将其转换为JSON对象：
{"ID001":{
"BookType":"[text]",
"author":"xyz abc",
"time":"01/12/2019[22:00] CST/PM"
},
{"ID002": {
"BookType":"[text]" ,
"author":"klj fgh",
"time":"19/02/2019[12:00] CST/AM"
}
}
我是Scala Spark的新手。任何想法如何将其转换。
使用具有良好实用性的杰克逊创建json。在您的情况下，可以使用以下代码完成
val mapper = new ObjectMapper`
val data = ("ID01", List(("BookType", "[text]"),("author", "xyz abc"),"time","01/12/2019[22:00] CST/PM")))
val id = mapper.createObjectNode()
val bookDetails = mapper.createObjectNode()
data._2.foreach(x => {bookDetails.put(x._1, x._2)})
id.set(data._1, bookDetails)
println(id.toString)
上面的输出如下
{"ID01":{"BookType":"[text]","author":"xyz abc","time":"01/12/2019[22:00] CST/PM"}}
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我来说两句