因此，基本上我想返回带有消息的字符串。
到目前为止，这就是我所拥有的，为什么我回来的名字仍然不确定，我已经进行了一系列测试，并且应该为第一个测试返回一个空的强度。
export const twoFer = (name) => {
let saying = "One for" + name + "," + "One for me"
let greeting = saying
if (name === '') {
let greeting = "One for you, One for me"
} else {
let greeting = "One for" + name + ",One for me"
}
return greeting;
};
我认为提供测试也是有用的。
import { twoFer } from './two-fer'
describe('twoFer()', () => {
test('no name given', () => {
expect(twoFer()).toEqual("One for you, one for me.")
})
xtest('a name given', () => {
expect(twoFer("Alice")).toEqual("One for Alice, one for me.")
})
xtest('another name given', () => {
expect(twoFer("Bob")).toEqual("One for Bob, one for me.")
})
})
编辑最终解决方案：
export const twoFer = (name = null) => {
if (!name) {
return "One for you, one for me."
} else {
return "One for " + name + "," + " one for me."
}
};
在您的示例中，name不是空字符串，而是undefined。而是尝试使用!name，这对于undefined，空字符串null等是正确的。
const twoFer = (name=null) => {
if (!name) {
return "One for you, One for me"
} else {
return "One for " + name + ", One for me"
}
};
console.log(twoFer());
console.log(twoFer(''));
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我来说两句