我在导入的.txt文件中转换日期时遇到问题,我想知道我做错了什么。
我通过以下方式导入数据:
df_TradingMonthlyDates = pd.read_csv(TradingMonthlyDates, dtype=str, sep=',') # header=True,
看起来像下表(日期代表月份的开始/结束并有标头Date
):
Date
0 2008-12-30
1 2008-12-31
2 2009-01-01
3 2009-01-02
4 2009-01-29
.. ...
557 2020-06-29
558 2020-06-30
559 2020-07-01
560 2020-07-02
561 2020-07-30
.. ...
624 2021-11-30
625 2021-12-01
626 2021-12-02
627 2021-12-30
628 2021-12-31
[629 rows x 1 columns]
<class 'pandas.core.frame.DataFrame'>
然后,我计算今天的日期:
df_EndDate = datetime.now().date()
我试图在此函数中应用上述数据,以获取给定日期之前的最接近日期(在我的情况下,给定日期=今天的日期):
# https://stackoverflow.com/questions/32237862/find-the-closest-date-to-a-given-date
def nearest(items, pivot):
return min([i for i in items if i < pivot], key=lambda x: abs(x - pivot))
date_output = nearest(df_TradingMonthlyDates, df_EndDate)
# date_output should be = 2020-07-02 given today's date of 2020-07-12
我收到的错误消息是,df_TradingMonthlyDates
它不是日期格式。因此,我试图将数据框转换为日期时间格式,但无法使其正常工作。
我试图将数据转换为日期格式的内容:
# df_TradingMonthlyDates["Date"] = pd.to_datetime(df_TradingMonthlyDates["Date"], format="%Y-%m-%d")
# df_TradingMonthlyDates = datetime.strptime(df_TradingMonthlyDates, "%Y-%m-%d").date()
# df_TradingMonthlyDates['Date'] = df_TradingMonthlyDates['Date'].apply(lambda x: pd.to_datetime(x[0], format="%Y-%m-%d"))
# df_TradingMonthlyDates = df_TradingMonthlyDates.iloc[1:]
# print(df_TradingMonthlyDates)
# df_TradingMonthlyDates = datetime.strptime(str(df_TradingMonthlyDates), "%Y-%m-%d").date()
# for line in split_source[1:]: # skip the first line
码:
import pandas as pd
from datetime import datetime
# Version 1
TradingMonthlyDates = "G:/MonthlyDates.txt"
# Import file where all the first/end month date exists
df_TradingMonthlyDates = pd.read_csv(TradingMonthlyDates, dtype=str, sep=',') # header=True,
print(df_TradingMonthlyDates)
# https://community.dataquest.io/t/datetime-and-conversion/213425
# df_TradingMonthlyDates["Date"] = pd.to_datetime(df_TradingMonthlyDates["Date"], format="%Y-%m-%d")
# df_TradingMonthlyDates = datetime.strptime(df_TradingMonthlyDates, "%Y-%m-%d").date()
# df_TradingMonthlyDates['Date'] = df_TradingMonthlyDates['Date'].apply(lambda x: pd.to_datetime(x[0], format="%Y-%m-%d"))
# df_TradingMonthlyDates = df_TradingMonthlyDates.iloc[1:]
# print(df_TradingMonthlyDates)
# df_TradingMonthlyDates = datetime.strptime(str(df_TradingMonthlyDates), "%Y-%m-%d").date()
# for line in split_source[1:]: # skip the first line # maybe header is the problem
print(type(df_TradingMonthlyDates))
df_TradingMonthlyDates = df_TradingMonthlyDates.datetime.strptime(df_TradingMonthlyDates, "%Y-%m-%d")
df_TradingMonthlyDates = df_TradingMonthlyDates.time()
print(df_TradingMonthlyDates)
df_EndDate = datetime.now().date()
print(type(df_EndDate))
# https://stackoverflow.com/questions/32237862/find-the-closest-date-to-a-given-date
def nearest(items, pivot):
return min([i for i in items if i < pivot], key=lambda x: abs(x - pivot))
date_output = nearest(df_TradingMonthlyDates, df_EndDate)
错误消息会有所不同,具体取决于我尝试转换数据类型的方式,但是我认为它们都注意到我的日期格式不成功:
df_TradingMonthlyDates = df_TradingMonthlyDates.datetime.strptime(df_TradingMonthlyDates, "%Y-%m-%d")
Traceback (most recent call last):
File "g:/till2.py", line 25, in <module>
df_TradingMonthlyDates = df_TradingMonthlyDates.datetime.strptime(df_TradingMonthlyDates, "%Y-%m-%d")
File "C:\Users\ID\AppData\Roaming\Python\Python38\site-packages\pandas\core\generic.py", line 5274, in __getattr__
return object.__getattribute__(self, name)
AttributeError: 'DataFrame' object has no attribute 'datetime'
df_TradingMonthlyDates["Date"] = pd.to_datetime(df_TradingMonthlyDates["Date"], format="%Y-%m-%d")
Traceback (most recent call last):
File "g:/till2.py", line 40, in <module>
date_output = nearest(df_TradingMonthlyDates, df_EndDate)
File "g:/till2.py", line 38, in nearest
return min([i for i in items if i < pivot], key=lambda x: abs(x - pivot))
File "g:/till2.py", line 38, in <listcomp>
return min([i for i in items if i < pivot], key=lambda x: abs(x - pivot))
TypeError: '<' not supported between instances of 'str' and 'datetime.date'
编辑:添加了方法3,它可能是最简单的方法.loc
,然后.iloc
你可以采取今天的日期和数据之间的差的绝对值最小采取略有不同的方法(与方法1或下面的方法#2),但你不能做一个关键的事情是环绕pd.to_datetime()
周围的datetime.date
物体df_EndDate
,以将其转换为,DatetimeArray
以便可以与您的Date
列进行比较。两者必须采用相同的格式DatetimeArray
才能进行比较。
方法1:
import pandas as pd
import datetime as dt
df_TradingMonthlyDates = pd.DataFrame({'Date': {'0': '2008-12-30',
'1': '2008-12-31',
'2': '2009-01-01',
'3': '2009-01-02',
'4': '2009-01-29',
'557': '2020-06-29',
'558': '2020-06-30',
'559': '2020-07-01',
'560': '2020-07-02',
'561': '2020-07-30',
'624': '2021-11-30',
'625': '2021-12-01',
'626': '2021-12-02',
'627': '2021-12-30',
'628': '2021-12-31'}})
df_TradingMonthlyDates['Date'] = pd.to_datetime(df_TradingMonthlyDates['Date'])
df_TradingMonthlyDates['EndDate'] = pd.to_datetime(dt.datetime.now().date())
df_TradingMonthlyDates['diff'] = (df_TradingMonthlyDates['Date'] - df_TradingMonthlyDates['EndDate'])
a=min(abs(df_TradingMonthlyDates['diff']))
df_TradingMonthlyDates = df_TradingMonthlyDates.loc[(df_TradingMonthlyDates['diff'] == a)
| (df_TradingMonthlyDates['diff'] == -a)]
df_TradingMonthlyDates
输出1:
Date EndDate diff
560 2020-07-02 2020-07-11 -9 days
如果您不想要多余的列,而只想要日期,则分配变量以创建系列而不是新列:
方法2:
d = pd.to_datetime(df_TradingMonthlyDates['Date'])
t = pd.to_datetime(dt.datetime.now().date())
e = (d-t)
a=min(abs(e))
df_TradingMonthlyDates = df_TradingMonthlyDates.loc[(e == a) | (e == -a)]
df_TradingMonthlyDates
输出2:
Date
560 2020-07-02
方法3:
df_TradingMonthlyDates['Date'] = pd.to_datetime(df_TradingMonthlyDates['Date'])
date_output = df_TradingMonthlyDates.sort_values('Date') \
.loc[df_TradingMonthlyDates['Date'] <=
pd.to_datetime(dt.datetime.now().date())] \
.iloc[-1,:]
date_output
输出3:
Date 2020-07-02
Name: 560, dtype: datetime64[ns]
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