首先，我刚开始学习它，因此对Python完全陌生。我对C ++有很多了解，而我只是想在Python中实现其中一些。
我已经对其进行了相当多的搜索，但是找不到符合我要求的解决方案。请看下面的代码，
import os
class _Getch:
"""Gets a single character from standard input. Does not echo to the
screen."""
def __init__(self):
try:
self.impl = _GetchWindows()
except:
print("Error!")
def __call__(self): return self.impl()
class _GetchWindows:
def __init__(self):
import msvcrt
def __call__(self):
import msvcrt
return msvcrt.getch()
def mainfun():
check = fh = True
while check:
fh = True
arr = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
print ("Welcome to Tic Tac Toe Game!!!\n\n")
print("Enter 1 to Start Game")
print("Enter 2 to Exit Game")
a = _Getch()
if a == "1":
while fh:
os.system("cls")
drawboard()
playermove()
fh = checkresult()
elif a == "2":
break
如您所见，我在这里要执行的操作是要求用户按下1和2之间的数字，然后将该数字存储在“ a”中，然后将其用于我的要求。
现在，我首先尝试使用它，
input('').split(" ")[0]
但这没有用。它要求我在键入1或2后始终按Enter键。因此，这不起作用。
然后我找到了Getch的此类，并实现了它。长话短说，它使我陷入了永无止境的循环，而我的结果现在是这样的，
Welcome to Tic Tac Toe Game!!!
Enter 1 to Start Game
Enter 2 to Exit Game
Press Enter to Continue....
Welcome to Tic Tac Toe Game!!!
Enter 1 to Start Game
Enter 2 to Exit Game
Press Enter to Continue....
Welcome to Tic Tac Toe Game!!!
Enter 1 to Start Game
Enter 2 to Exit Game
Press Enter to Continue....
而且这是一个永无止境的循环...即使我按下“ 1”或“ 2”之类的任何键，它仍然不会停止并继续执行此操作，并且不会输入任何功能。
我想要的是与此类似的功能，
换句话说，我只想要Python中C ++的getch（）命令的替代方法。我已经做了很多尝试来找到它，但是没有找到。请问我一个问题，该问题可以为该确切问题提供解决方案，或者在此处提供解决方案。谢谢。
编辑：请注意，这不是完整的代码。我只提供了相关的代码。如果有人需要查看整个代码，我也很乐意分享。
完整的代码如下，
import os
import keyboard
def getch():
alphabet = list(map(chr, range(97, 123)))
while True:
for letter in alphabet: # detect when a letter is pressed
if keyboard.is_pressed(letter):
return letter
for num in range(10): # detect numbers 0-9
if keyboard.is_pressed(str(num)):
return str(num)
arr = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
playerturn = 1
def drawboard():
global playerturn
print("Player 1 (X) - Player 2 (O)\n")
print("Turn: Player " + str(playerturn))
print("\n")
for i in range(3):
print (" ", end='')
for j in range(3):
print(arr[i][j], end='')
if j == 2:
continue
print(" | ", end='')
if i == 2:
continue
print("")
print("____|____|____")
print(" | | ")
def playermove():
global playerturn
row = col = 0
correctmove = False
print("\n\nMake your Move!\n")
while not correctmove:
row = int(input("Enter Row: "))
col = int(input("Enter Col: "))
if (3 > row > -1) and (-1 < col < 3):
for i in range(3):
for j in range(3):
if arr[row][col] == 0:
correctmove = True
if playerturn == 1:
arr[row][col] = 1
else:
arr[row][col] = 2
playerturn += 1
if playerturn > 2:
playerturn = 1
if not correctmove:
print ("Wrong Inputs, please enter again, ")
def checkwin():
for player in range(1, 3):
for i in range(3):
if arr[i][0] == player and arr[i][1] == player and arr[i][2] == player: return player
if arr[0][i] == player and arr[1][i] == player and arr[2][i] == player: return player
if arr[0][0] == player and arr[1][1] == player and arr[2][2] == player: return player
if arr[0][2] == player and arr[1][1] == player and arr[2][0] == player: return player
return -1
def checkdraw():
for i in range(3):
for j in range(3):
if arr[i][j] == 0:
return False
return True
def checkresult():
check = checkwin()
if check == 1:
os.system('cls')
drawboard()
print("\n\nPlayer 1 has won the game!!\n")
elif check == 2:
os.system('cls')
drawboard()
print("\n\nPlayer 2 has won the game!!\n")
elif check == 3:
os.system('cls')
drawboard()
print("\n\nThe game has been drawn!!\n")
else:
return True
return False
def mainfun():
check = fh = True
while check:
os.system("cls")
fh = True
arr = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
print ("Welcome to Tic Tac Toe Game!!!\n\n")
print("Enter 1 to Start Game")
print("Enter 2 to Exit Game")
a = getch()
if a == "1":
while fh:
os.system("cls")
drawboard()
playermove()
fh = checkresult()
elif a == "2":
break
print ("Press any key to continue...")
getch()
mainfun()
EDIT2：通过使用键盘模块解决了问题...下一个问题是在调用getch（）函数后如何删除存储在输入缓冲区中的数据？因为缓冲区中的数据正显示在下一个输入中（当我输入行和列时），所以我不希望发生这种情况。我喜欢Linux而不是Windows（或Pycharm）的解决方案
看来此功能不在标准python库中，但您可以重新创建它。
首先，安装模块“键盘”
$ pip3 install keyboard
然后，您可以使用keyboard.is_pressed（）查看是否按下了任何一个字符。
import keyboard # using module keyboard
import string # use this to get the alphabet
print("Input a character")
def getch():
alphabet = list(string.ascii_lowercase)
while True:
for letter in alphabet: # detect when a letter is pressed
if keyboard.is_pressed(letter):
return letter
for num in range(10): # detect numbers 0-9
if keyboard.is_pressed(str(num)):
return str(num)
answer = getch()
print("you choose " + answer)
编辑：对于unix，您需要使用sudo运行脚本。此代码在Windows上应该可以正常工作。
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