对C＃类的肥皂响应始终返回空值

debugcn 发表于 Dev

卡尔图斯汗

我很难解析来自Web服务的soap响应并将其转换为c＃对象。我所做的总是返回null元素。这是我的回应。

<soapenv:Envelope xmlns:soapenv='http://schemas.xmlsoap.org/soap/envelope/' 
 xmlns:tem='http://tempuri.org/'>
 <soapenv:Header/> <soapenv:Body>
 <tem:Response><tem:Result>
  <RETN>108</RETN><DESC> This is an error</DESC></tem:Result></tem:Response>
   </soapenv:Body>
 </soapenv:Envelope>

这就是我解析此响应的方式。

var xDoc = XDocument.Parse(response);
var xLoginResult = xDoc.Root.Descendants().FirstOrDefault(d => d.Name.LocalName.Equals("Result"));
var serializer = new XmlSerializer(typeof(Result));
using (var reader = xLoginResult.CreateReader())
{
    var convertedResonse= (Result)serializer.Deserialize(reader);
    // inside this convertedResonse RETN and  DESC is alway null
}

这是我的结果类

   [XmlRoot(ElementName = "Result", Namespace = "http://tempuri.org/")]
    public class Result
    {
        [XmlElement("RETN")]
        public string RETN { get; set; }
        [XmlElement("DESC")]
        public string DESC { get; set; }
    }

    [XmlRoot(ElementName = "Response", Namespace = "http://tempuri.org/")]
    public class Response
    {
        [XmlElement(ElementName = "Result", Namespace = "http://tempuri.org/")]
        public Result Result { get; set; }
    }

    [XmlRoot(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
    public class Body
    {
        [XmlElement(ElementName = "Response", Namespace = "http://tempuri.org/")]
        public Response Response { get; set; }
    }

    [XmlRoot(ElementName = "Envelope", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
    public class Envelope
    {
        [XmlElement(ElementName = "Header", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
        public string Header { get; set; }
        [XmlElement(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
        public Body Body { get; set; }
        [XmlAttribute(AttributeName = "soapenv", Namespace = "http://www.w3.org/2000/xmlns/")]
        public string Soapenv { get; set; }
        [XmlAttribute(AttributeName = "tem", Namespace = "http://www.w3.org/2000/xmlns/")]
        public string Tem { get; set; }
    }

内部的convertedResonse值始终为null。任何想法将不胜感激？

萨吉德

对于问题中发布的Xml，您不需要使用XmlSerializer，只需XDocument使用Linq到Xml就足够了，例如以下代码：

1-创建命名空间：

XNamespace xn = "http://tempuri.org/";

2-将XDocument的查询修改为：

Result result = xDoc
    .Descendants(xn + "Result")
    .Select(x => new Result { DESC = x.Element("DESC").Value, RETN = x.Element("RETN").Value })
    .FirstOrDefault();

Console.WriteLine($"DESC:{result.DESC}, RETN:{result.RETN}");

结果