我的输入文件是没有扩展名的html文件。所需的输出是来自root_dir的所有文件的正则表达式匹配的URL，并将结果合并到单个文件中。我的正则表达式工作正常，我可以从单个文件输出结果。
import re
with open('/Users/files/filename') as f:
for line in f:
urls = re.findall (r"([\w%~\+-=]*\.mp3)", line);
print (*urls)
我可以使用glob，但不确定如何：
import glob
import re
root_dir = '/Users/files/'
for filename in glob.iglob(root_dir + '**/*.*', recursive=True):
urls = re.findall (r"([\w%~\+-=]*\.mp3)", line);
print (*urls)
采用
import re, glob # Import the libraries
root_dir = r'/Users/files' # Set root directory
save_to_file = r'/Users/urls_extracted.txt' # File path to save results to
all_files = glob.glob("{}/*".format(root_dir)) # Get a glob with filepaths
with open(save_to_file, 'w') as fw: # Open stream to write to
for filename in all_files: # Iterate over the files
with open(filename, 'r') as fr: # Open file to read from
for url in re.findall(r"[\w%~+\-=]*\.mp3", fr.read()): # Get all matches and iterate over them
fw.write("{}\n".format(url)) # Write each URL to write stream
请注意，如果要表示-字符而不是范围，则必须在正则表达式中将破折号转义。
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句