哪个UserControl调用事件MouseEnter？

debugcn 发表于 Dev

塔蒂亚娜M

我有一个清单，UserControl我想知道哪个UserControl正在调用event MouseEnter。我UserControl在上添加了多个TableLayoutPanel。

List<MyUserControl> form = new List<MyUserControl>();

for (int x = 0; x < dt.Rows.Count; x++)
{
    tableLayoutPanel1.ColumnStyles.Add(new ColumnStyle(SizeType.Absolute, 200));
    if (x == 0)
       tableLayoutPanel1.RowStyles.Add(new RowStyle(SizeType.AutoSize));
    form.Add(new MyUserControl());
}

for (int x = 0; x < form.Count; x++)
{    
    form[x].MouseEnter += new EventHandler(Form_MouseEnter);
    tableLayoutPanel1.Controls.Add(form[x], x, 0);
}

我如何找出哪个UserControl事件被激活？

IV软件

最大的不同是，如果给新的MyUserControl一个Name，因为默认的Name是一个空字符串。您可以尝试将代码更改为此，看看是否有帮助？

List<MyUserControl> form = new List<MyUserControl>();

for (int x = 0; x < 5; x++)
{
    tableLayoutPanel1.ColumnStyles.Add(new ColumnStyle(SizeType.Absolute, 200));
    if (x == 0)
        tableLayoutPanel1.RowStyles.Add(new RowStyle(SizeType.AutoSize));

    // vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
    // Here are the changes
    MyUserControl myUserControl = new MyUserControl();
    myUserControl.Name = "MyUserControl_" + x.ToString("D2"); // Name it! (Default is "")                
    myUserControl.MouseEnter += MyUserControl_MouseEnter;     // Hook the MouseEnter here
    myUserControl.Codigo = 1000 + x;                          // Example to set Codigo     
    // ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

    form.Add(myUserControl); // NOTE! This is changed from 'new MyUserControl()'.
}

for (int x = 0; x < form.Count; x++)
{
    tableLayoutPanel1.Controls.Add(form[x], x, 0);
}

现在，处理程序如下所示：

private void MyUserControl_MouseEnter(object sender, EventArgs e)
{
    MyUserControl myUserControl = (MyUserControl)sender;
    Debug.WriteLine(
        "MouseEnter Detected: " + myUserControl.Name + 
        " - Value of Codigo is: " + myUserControl.Codigo);
}

...在哪里（根据您对Codigo的评论）...

class MyUserControl : UserControl
{
    public int Codigo 
    { 
        set 
        { 
            test = value; 
        } 
        get 
        { 
            return test; 
        } 
    }
    int test = 0;
    // Of course there is more implementation of MyUserControl that follows...
}

我真的希望这可以帮助您解决遇到的问题。

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