def main(start,end):
range(start,end)
total=0
for nums in range(start,end):
if nums%3 ==0 or nums%5==0:
total=(total)+(nums)
return total
print(main(int(input("enter start ")),int(input("enter end "))))
如果我输入1到100,答案将为2318
如何在不再次输入的情况下打印号码范围列表?
print(list(range(start,end)))
例如,我想要[1,2,3,4,...,99]
但不输入,但使用上面给出的原始输入
这对你有帮助
def main(start,end):
total=0
l = []
for nums in range(start,end):
l.append(nums)
if nums%3 ==0 or nums%5==0:
total=(total)+(nums)
print(l)
return total
print(main(int(input("enter start ")),int(input("enter end "))))
输出:
enter start 1
enter end 100
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
2318
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