如何在React Navigation 5中将父函数传递给子屏幕？

最近，我开始使用React Native0.61.5和React导航5.x。现在，我需要将父函数传递给子屏幕。例如，我想通过按嵌套在StackNavigator中的TabNavigator选项卡中的按钮来更改导航栏图标。以前（3.x版导航）getActiveChildNavigationOptions用于满足我的需求，但现在已将其删除。因此，实现此目标的唯一方法是将自定义函数传递给子组件。

在示例代码中，我想从更改XXXXXXXX为YYYYYYYYY：

const TabA = ({ route }) => (
  <View>
    <Text>Tab A</Text>
      <Button 
        title="Change header"
        onPress={() => route.params.setHeaderRightName("YYYYYYYYY")}/>
  </View>
)

const TabB = () => <><Text>Tab B</Text></>

const Tabs = createBottomTabNavigator();
const TabsNavigator = ({ navigation }) => {
  const [headerRightName, setHeaderRightName] = useState("XXXXXXXX");

  useLayoutEffect(() => navigation.setOptions({
    headerRight: () => <MyNavIcon name={headerRightName}/>
  }), [headerRightName]);

  return (
    <Tabs.Navigator>
      <Tabs.Screen name="tab-a" component={TabA} initialParams={{ setHeaderRightName }} />
      <Tabs.Screen name="tab-b" component={TabB} />
    </Tabs.Navigator>
  );
}

const Stack = createStackNavigator();
export default App = () => (
  <NavigationContainer>
    <Stack.Navigator>
      <Stack.Screen name="tabs" component={TabsNavigator} />
      <Stack.Screen name="another-screen" component={AnotherScreen} />
    </Stack.Navigator>
  </NavigationContainer>
)

一切正常，但我收到此警告：

全文：

Non-serializable values were found in the navigation state, which can break usage such as persisting and restoring state. This might happen if you passed non-serializable values such as function, class instances etc. in params. If you need to use components with callbacks in your options, you can use 'navigation.setOptions' instead. See https://reactnavigation.org/docs/troubleshooting#i-get-the-warning-non-serializable-values-were-found-in-the-navigation-state for more details.

因此，如果警告说我无法使用路由参数传递功能，该如何将功能从父级传递给子级？