如何在单击按钮时将部分视图呈现为模式弹出窗口？

以下示例应有助于满足您使用jQuery Ajax将部分视图呈现为模式弹出窗口的要求，请进行检查。

All.cshtml

@model IEnumerable<Venue>

@{
    ViewData["Title"] = "All";
}

<h1>All</h1>

<table class="table table-hover">
    <thead>
    <th> Property Name </th>
    <th colspan="2">Action</th>
    </thead>
    <tbody>
        @foreach (var x in Model)
        {
            <tr>
                <td>
                    @x.Name
                </td>
                <td>
                    <a class="btn btn-default btn-sm" id="@x.Id" onclick="Details(this.id)">Show</a>
                </td>
            </tr>
        }
    </tbody>
</table>

<div class="modal fade" id="myModal" role="dialog">
    <div class="modal-dialog">

        <!-- Modal content-->
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal">&times;</button>
                <h4 class="modal-title">Details</h4>
            </div>
            <div class="modal-body">
            </div>
            <div class="modal-footer">
                <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            </div>
        </div>
    </div>
</div>

@section scripts{
    <script>
        function Details(id) {
            $.get("@Url.Action("ShowpopUp","Owner")/" + id,
                function (data) {
                    $('.modal-body').html(data);
                });

                $("#myModal").modal("show");
        }
    </script>
}

ShowpopUp 行动

public IActionResult ShowpopUp(int id)
{
    var venue = _context.Venues.FirstOrDefault(x => x.Id == id);

    //specify the name or path of the partial view
    return PartialView("_VenueDetail", venue);
}

_VenueDetail.cshtml（“视图/共享”文件夹下的部分视图）

@model Venue

    <h1>Venue Details</h1>

<h2>Id: @Model.Id</h2>
<h2>Name: @Model.Name</h2>

测试结果