我有一个要解析的长字符串的DataFrame列。我是regex的新手,还没有使用过它。我下面的内容最多只会返回名字。我想知道对于正则表达式或创建字典进行迭代是否更容易解析此字符串。这是我目前所拥有的。顺序并不总是相同的(C,W,D,G,UTIL),我将编写一个for循环来遍历多行,就像这样。
import pandas as pd
import numpy as np
import re
df = pd.DataFrame(data=np.array([['C Mark Scheifele C Pierre-Luc Dubois UTIL Zach Parise W Mats Zuccarello W Oliver Bjorkstrand W Nick Foligno D Ryan Suter D Seth Jones G Devan Dubnyk'],['UTIL Kyle Connor C Pierre-Luc Dubois C Boone Jenner W Mats Zuccarello W Oliver Bjorkstrand W Nick Foligno D Ryan Suter D Seth Jones G Devan Dubnyk']]), columns=['Lineup'])
df['C1'] = re.findall(r" C \w+",str(df['Lineup']))
df['C2'] = re.findall(r'C \w+',str(df['Lineup']))
df['W1'] = re.findall(r'W \w+',str(df['Lineup']))
df['W2'] = re.findall(r'W \w+',str(df['Lineup']))
df['W3'] = re.findall(r'W \w+',str(df['Lineup']))
df['D1'] = re.findall(r'D \w+',str(df['Lineup']))
df['D1'] = re.findall(r'D \w+',str(df['Lineup']))
df['G']= re.findall(r'G \w+',str(df['Lineup']))
df['UTIL'] = re.findall(r'UTIL \w+',str(df['Lineup']))
我正在寻找将这些值存储到DF中。
df['C1'] = Mark Scheifele
df['C2'] = Pierre-Luc Dubois
df['W1'] = Mats Zuccarello
df['W2'] = Oliver Bjorkstrand
df['W3'] = Nick Foligno
df['D1'] = Ryan Suter
df['D2'] = Seth Jones
df['G']= Devan Dubnyk
df['UTIL'] = Zach Parise
结果数据帧 df_result = pd.DataFrame(data=np.array([['Mark Scheifele','Pierre-Luc Dubois','Mats Zuccarello','Oliver Bjorkstrand','Nick Foligno','Ryan Suter','Seth Jones','Devan Dubnyk','Zach Parise'],['Boone Jenner','Pierre-Luc Dubois','Mats Zuccarello','Oliver Bjorkstrand','Nick Foligno','Ryan Suter','Seth Jones','Devan Dubnyk','Kyle Connor']]), columns=['C1','C2','W1','W2','W3','D1','D2','G','UTIL'])
import pandas as pd
import numpy as np
import re
def calc_col(col):
'''This function takes a string,
finds the upper case letters or words placed as delimeter,
converts it to a list,
adds a number to the list elements if recurring.
Eg. input list :['W','W','W','D','D','G','C','C','UTIL']
o/p list: ['W1','W2','W3','D1','D2','G','C1','C2','UTIL']
'''
col_list = re.findall(" ?([A-Z]+) ", col)
col_list2 = []
for i in col_list:
cnt = col_list.count(i)
if cnt == 1:
col_list2.append(i)
if cnt > 1:
if i in " ".join(col_list2):
continue;
col_list2 += [i+str(k) for k in range(1,cnt+1)]
return col_list2
df = pd.DataFrame(data=np.array([['C Mark Scheifele C Pierre-Luc Dubois UTIL Zach Parise W Mats Zuccarello W Oliver Bjorkstrand W Nick Foligno D Ryan Suter D Seth Jones G Devan Dubnyk'],['UTIL Kyle Connor C Pierre-Luc Dubois C Boone Jenner W Mats Zuccarello W Oliver Bjorkstrand W Nick Foligno D Ryan Suter D Seth Jones G Devan Dubnyk']]), columns=['Lineup'])
extr_row = df['Lineup'].replace(to_replace =" ?[A-Z]+ ", value="\n", regex = True) #split the rows on
df_final = pd.DataFrame(columns = sorted(calc_col(df['Lineup'].iloc[0]))) #Create an empty data frame df3 with sorted columns
for i in range(len(extr_row)): #traverse all the rows in the original dataframe and append the formatted rows to df3
df_temp = pd.DataFrame((extr_row.values[i].split("\n")[1:])).T
df_temp.columns = calc_col(df['Lineup'].iloc[i])
df_temp= df_temp[sorted(df_temp)]
df_final = df_final.append(df_temp)
df_final.reset_index(drop = True, inplace = True)
df_final
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