我说过这个数据框：
gene0 1 2 3
gene1 0 0 5
gene2 6 8 0
gene3 5 5 5
0 0 5
1 2 3
并且我想将“未命名”列中的数字与基因相关联，使其具有以下特征：
gene0 1 2 3
gene1 0 0 5
gene2 6 8 0
gene3 5 5 5
gene1 0 0 5
gene0 1 2 3
最好的方法是什么？我需要使用linux还是R？
我们可以使用match从base R
a1 <- do.call(paste, df1[-1])
df1$V1 <- df1$V1[match(a1, unique(a1))]
df1$V1
#[1] "gene0" "gene1" "gene2" "gene3" "gene1" "gene0"
使用OP的数据集
df1 <- read.csv("newest.csv", stringsAsFactors = FALSE)
df1$id[df1$id == ""] <- NA
a1 <- do.call(paste, df1[-1])
df1$id <- df1$id[match(a1, unique(a1))]
length(unique(df1$id))
#[1] 621
head(df1$id, 20)
#[1] "pop13_110" "pop1_2" "pop16_108" "pop2_10" "pop2_2" "pop2_3" "pop2_4" "pop2_5" "pop2_6" "pop2_7" "pop2_8"
#[12] "pop2_9" "pop2_10" "pop2_11" "pop7_81" "pop2_13" "pop2_15" "pop2_15" "pop2_16" "pop22_20"
tail(df1$id, 20)
# [1] "pop22_2" "pop22_3" "pop22_4" "pop22_5" "pop22_8" "pop22_9" "pop13_60" "pop16_131" "pop23_11" "pop22_25" "pop22"
#[12] "pop22_14" "pop22_15" "pop22_32" "pop22_28" "pop16_56" "pop22_18" "pop9_9" "pop22_21" "pop22_22"
df1 <- structure(list(V1 = c("gene0", "gene1", "gene2", "gene3", NA,
NA), V2 = c(1L, 0L, 6L, 5L, 0L, 1L), V3 = c(2L, 0L, 8L, 5L, 0L,
2L), V4 = c(3L, 5L, 0L, 5L, 5L, 3L)), class = "data.frame",
row.names = c(NA,
-6L))
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