GEKKO为什么不进行初始测量？

debugcn 发表于 Dev

丹尼尔·希尔

在使用GEKKO对具有初始测量值的动态系统进行建模时，即使打开了FSTATUS，GEKKO似乎也完全忽略了测量值。是什么原因造成的？如何使GEKKO识别初始测量值？

我希望求解器将初始测量结果考虑在内，从而相应地调整解决方案。

from gekko import GEKKO
import numpy as np
import matplotlib.pyplot as plt 

# measurement
tm = 0
xm = 25

m = GEKKO()
m.time = np.linspace(0,20,41)
tau = 10
b = m.Param(value=50)
K = m.Param(value=0.8)

# Manipulated Variable
u = m.MV(value=0, lb=0, ub=100)
u.STATUS = 1  # allow optimizer to change
u.DCOST = 0.1
u.DMAX = 30

# Controlled Variable
x = m.CV(value=0,name='x')
x.STATUS = 1  # add the SP to the objective
m.options.CV_TYPE = 2 # squared error
x.SP = 40     # set point
x.TR_INIT = 1 # set point trajectory
x.TAU = 5     # time constant of trajectory
x.FSTATUS = 1
x.MEAS = xm

# Process model
m.Equation(tau*x.dt() == -x + K*u)
m.options.IMODE = 6 # control
m.solve()

# get additional solution information
import json
with open(m.path+'//results.json') as f:
        results = json.load(f)
plt.figure()
plt.subplot(2,1,1)
plt.plot(m.time,u.value,'b-',label='MV Optimized')
plt.legend()
plt.ylabel('Input')
plt.subplot(2,1,2)
plt.plot(tm,xm,'ro', label='Measurement')
plt.plot(m.time,results['x.tr'],'k-',label='Reference Trajectory')
plt.plot(m.time,results['x.bcv'],'r--',label='CV Response')
plt.ylabel('Output')
plt.xlabel('Time')
plt.legend()
plt.show()

约翰·海登格伦

Gekko忽略了MPC初始化的第一个周期的测量。如果您进行其他求解，则它将使用度量。

m.solve() # for MPC initialization

x.MEAS = xm
m.solve() # update initial condition with measurement

反馈状态（FSTATUS）是一阶过滤器，用于介于0（无更新）和1（完整的测量更新）之间的测量。

MEAS = LSTVAL * (1-FSTATUS) + MEAS * FSTATUS

然后将新的测量值（MEAS）用于偏差计算。有无偏（原始预测不受测量影响）模型预测和有偏模型预测。偏差被计算为无偏差模型预测和测量之间的差。

BIAS = MEAS - UNBIASED_MODEL

from gekko import GEKKO
import numpy as np
import matplotlib.pyplot as plt 

# measurement
tm = 0
xm = 25

m = GEKKO()
m.time = np.linspace(0,20,41)
tau = 10
b = m.Param(value=50)
K = m.Param(value=0.8)

# Manipulated Variable
u = m.MV(value=0, lb=0, ub=100)
u.STATUS = 1  # allow optimizer to change
u.DCOST = 0.1
u.DMAX = 30

# Controlled Variable
x = m.CV(value=0,name='x')
x.STATUS = 1  # add the SP to the objective
m.options.CV_TYPE = 2 # squared error
x.SP = 40     # set point
x.TR_INIT = 1 # set point trajectory
x.TAU = 5     # time constant of trajectory
x.FSTATUS = 1

# Process model
m.Equation(tau*x.dt() == -x + K*u)
m.options.IMODE = 6 # control
m.solve(disp=False)

m.options.TIME_SHIFT = 0
x.MEAS = xm
m.solve(disp=False)
# turn off time shift, only for initialization
m.options.TIME_SHIFT = 1

# get additional solution information
import json
with open(m.path+'//results.json') as f:
        results = json.load(f)
plt.figure()
plt.subplot(2,1,1)
plt.plot(m.time,u.value,'b-',label='MV Optimized')
plt.legend()
plt.ylabel('Input')
plt.ylim([-5,105])
plt.subplot(2,1,2)
plt.plot(tm,xm,'ro', label='Measurement')
plt.plot(m.time,results['x.tr'],'k-',label='Reference Trajectory')
plt.plot(m.time,results['x.bcv'],'r--',label='CV Response Biased')
plt.plot(m.time,x.value,'g:',label='CV Response Unbiased')
plt.ylim([-1,41])
plt.ylabel('Output')
plt.xlabel('Time')
plt.legend()
plt.show()

这是当前的工作方式，因为LSTVAL上述计算没有模型预测或没有偏见。第一个周期计算这些值，并允许后续周期进行更新。如果确实在第一个循环中需要更新的值，则可以m.option.TIME_SHIFT=0在第二个求解中使用选项进行求解，以不更新模型的初始条件。您将需要更改TIME_SHIFT=1以使后续循环具有动态模型的预期时间进度。