我如何通过一个唯一的用户名合并多个关联数组

debugcn 发表于 Dev

阿图尔·门德斯（Artur Mendes）

我需要将3个关联数组合并为具有唯一用户名的单个关联数组

我的3个数组如下所示：（var_export）

acceptedArray array ( 'user1' => 1, 'user2' => 1, 'user3' => 1, )

未完成的数组 array ( 'user1' => 1, 'user3' => 2, 'user15' => 3, )

denyArray array ( 'user1' => 1, 'user15' => 22, 'user20' => 5, )

每个数组都是查询提取的array_count_values个。

我需要这样的输出：

$return = [
    ['username' => user1, 'accepted' => 1, 'pending' => 3 , 'denied' => 1]
    ['username' => user2, 'accepted' => 1, 'pending' => 4]
];

我试过了（是的，完全关闭了）：

foreach ($acceptedUsers as $key => $value) {
    $return[] = array('username' => $key, 'accepted' => $value);
}
foreach ($pendingUsers as $key => $value) {
    $return[] = array('username' => $key, 'pending' => $value);
}

但这会创建重复项，而不是追加。

米克马克萨

迭代单个数组，并将用户名用作分组的键。

代码：（演示）

$acceptedUsers = ["user1" => 1, "user2" => 1, "user3" => 1];

$pendingUsers = ["user1" => 3, "user2" => 4, "user5" => 2];

$deniedUsers = ["user1" => 1, "user15" => 4, "user10" => 2];

foreach ($acceptedUsers as $user => $count) {
    $result[$user]['accepted'] = $count;
}
foreach ($pendingUsers as $user => $count) {
    $result[$user]['pending'] = $count;
}

foreach ($deniedUsers as $user => $count) {
    $result[$user]['denied'] = $count;
}

var_export($result);

而且，如果您需要子数组中的用户名，那么再次循环遍历这些组可能会比较麻烦。https://3v4l.org/0rUv5

foreach ($acceptedUsers as $user => $count) {
    $grouped[$user]['accepted'] = $count;
}
foreach ($pendingUsers as $user => $count) {
    $grouped[$user]['pending'] = $count;
}

foreach ($deniedUsers as $user => $count) {
    $grouped[$user]['denied'] = $count;
}

foreach ($grouped as $user => $row) {
    $result[] = ['username' => $user] + $row;
}
var_export($result);

否则，请isset()在循环2和3中进行检查。https://3v4l.org/3sstg

foreach ($acceptedUsers as $user => $count) {
    $grouped[$user]['username'] = $user;
    $grouped[$user]['accepted'] = $count;
}
foreach ($pendingUsers as $user => $count) {
    if (!isset($grouped[$user])) {
        $grouped[$user]['username'] = $user;
    }
    $grouped[$user]['pending'] = $count;
}

foreach ($deniedUsers as $user => $count) {
    if (!isset($grouped[$user])) {
        $grouped[$user]['username'] = $user;
    }
    $grouped[$user]['denied'] = $count;
}

var_export(array_values($grouped));

或残酷地强制用户名（无条件覆盖先前存在的用户名元素）https://3v4l.org/I1kBu

foreach ($acceptedUsers as $user => $count) {
    $grouped[$user]['username'] = $user;
    $grouped[$user]['accepted'] = $count;
}
foreach ($pendingUsers as $user => $count) {
    $grouped[$user]['username'] = $user;
    $grouped[$user]['pending'] = $count;
}

foreach ($deniedUsers as $user => $count) {
    $grouped[$user]['username'] = $user;
    $grouped[$user]['denied'] = $count;
}

var_export(array_values($grouped));

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