列表列表中的改组对

debugcn 发表于 Dev

皮特

给出如下列表：

aList = [["1","Number1", "2", "Number2","3","Number3", "4", "Number4"],["3","Number3", "1", "Number1","2","Number2", "4", "Number4"]]

我试图将子列表中的每两个元素改组以得到类似以下内容：

aListNew = [["3","Number3", "1", "Number1","4","Number4", "2", "Number2"],["2","Number2", "3", "Number3","1","Number1", "4", "Number4"]]

因此重要的是，两个连续的弦在混洗时保持在一起。

西蒙·N

您可以通过多种方式执行此操作。您不会给出任何尝试或失败原因的指示。不过，由于尚未回答或未解决此问题，因此这里有一些代码。请查看发布指南，以便您以后的帖子将产生更多答案，并且不太可能被关闭。

import random

aList = [["1","Number1", "2", "Number2","3","Number3", "4", "Number4"],["3","Number3", "1", "Number1","2","Number2", "4", "Number4"]]
alist_alt = []

for sublist in aList:
    l = len(sublist)
    r = list(range(0, l ,2))
    random.shuffle(r)

    sublist_alt=[]
    for i in r:
        sublist_alt.append(sublist[i])
        sublist_alt.append(sublist[i+1])

    alist_alt.append(sublist_alt)

print(alist_alt)

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