我正在尝试创建一个form(boqform)
将数据发布到中,model(boqmodel)
但我正在
typeerror is_valid()缺少1个必需的位置参数:“ self”
我需要在html模板上显示一个名为boqform的表单,并将输入用户的数据发布到boqmodel中
我的观点:
def boqmodel1(request):
if boqform.is_valid():
form = boqform(request.POST)
obj=form.save(commit=False)
obj.save()
context = {'form': form}
return render(request, 'create.html', context)
else:
context = {'error': 'The post has been successfully created. Please enter boq'}
return render(request, 'create.html', context)
追溯:
File "C:\Users\TRICON\AppData\Local\Programs\Python\Python38-32\lib\site-packages\django\core\handlers\exception.py" in inner
34. response = get_response(request)
File "C:\Users\TRICON\AppData\Local\Programs\Python\Python38-32\lib\site-packages\django\core\handlers\base.py" in _get_response
115. response = self.process_exception_by_middleware(e, request)
File "C:\Users\TRICON\AppData\Local\Programs\Python\Python38-32\lib\site-packages\django\core\handlers\base.py" in _get_response
113. response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\Users\TRICON\Desktop\ind\ind\boq\views.py" in boqmodel1
23. if boqform.is_valid():
Exception Type: TypeError at /boq/create/
Exception Value: is_valid() missing 1 required positional argument: 'self'
您正在尝试is_valid()
在类上调用实例函数boqform
。您需要获取boqform
first的实例。切换功能的第1和第2行应该可以解决此问题:
def boqmodel1(request):
form = boqform(request.POST)
if form.is_valid():
obj=form.save(commit=False)
obj.save()
context = {'form': form}
return render(request, 'create.html', context)
else:
context = {'error': 'The post has been successfully created. Please enter boq'}
return render(request, 'create.html', context)
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