[{
id: 1
name: "abcd",
value: 123,
type: "foo"
},
{
id: 1
name: "abcd",
value: 321,
type: "faa"
},
{
id: 2
name: "dcba",
value: 456,
type: "baa"
}]
我想实现以下目标：
[{
id: 1,
name: "abcd",
value: [123, 321],
type: ["foo", "faa"]
},
{
id: 2
name: "dcba",
value: [456],
type: ["baa"]
}]
额外的键具有相同的值。
我们的想法是组由id，则图中的每个对象组，挑id和name从第一对象，提取所有value与type从在该组，转置的所有对象，并压缩至另一对象，并且将它们合并。
const { pipe, groupBy, prop, values, map, converge, merge, head, pick, props, transpose, zipObj } = R
const fn = pipe(
groupBy(prop('id')), // groupBy the id
values, // convert the object of groups to array of groups
map(converge(merge, [ // map each group by merging the results of...
pipe(head, pick(['id', 'name'])), // getting the id and name from the 1st item
pipe(map(props(['value', 'type'])), transpose, zipObj(['value', 'type'])) // extract the value and type and zipping to an object
]))
)
const data = [{
id: 1,
name: "abcd",
value: 123,
type: "foo"
},
{
id: 1,
name: "abcd",
value: 321,
type: "faa"
},
{
id: 2,
name: "dcba",
value: 456,
type: "baa"
}]
const result = fn(data)
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