如何缩短或清理此python代码？

debugcn 发表于 Dev

布尔霍尔姆·拉里

我进行了一项家庭作业，编写了一个程序，该程序将高速公路编号作为输入，并输出该高速公路是主要公路还是辅助公路，东西/北/南/北，如果是辅助公路，则服务于哪个主要公路。这是我的代码，获得了我的好评，但是我是一个初学者，所以必须有一种较短的编写方法。有人介意清理吗？

highway_number = int(input())

if highway_number >= 1 and highway_number <= 99:
    prim = 'is primary,'
    if (highway_number % 2) == 0:
        print('The', highway_number, prim, 'going east/west.')
    else:
        print('The', highway_number, prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if (highway_number % 2) == 0:
        print('The', highway_number, aux, 'serving the %d, going east/west.' % (highway_number%100))
    else:
        print('The', highway_number, aux, 'serving the %d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

此处有290个输出：

The 290 is auxiliary, serving the 90, going east/west.

rdas

用于

1）链式比较

2）F弦

3）使用0/1的布尔值的内联if语句

使代码更短

highway_number = int(input())

if 1 <= highway_number <= 99:
    direction = 'east/west' if highway_number % 2 else 'north/south'
    print(f'The {highway_number} is primary, going {direction}')
elif 100 <= highway_number <= 999:
    direction = 'north/south' if highway_number % 2 else 'east/west'
    print(f'The {highway_number} is auxiliary, serving the {highway_number%100}, going {direction}')
else:
    print(highway_number, 'is not a valid interstate highway number.')

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